Integrand size = 23, antiderivative size = 63 \[ \int \frac {\cot ^3(c+d x)}{a+b \sin ^2(c+d x)} \, dx=-\frac {\csc ^2(c+d x)}{2 a d}-\frac {(a+b) \log (\sin (c+d x))}{a^2 d}+\frac {(a+b) \log \left (a+b \sin ^2(c+d x)\right )}{2 a^2 d} \]
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Time = 0.12 (sec) , antiderivative size = 63, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.087, Rules used = {3273, 78} \[ \int \frac {\cot ^3(c+d x)}{a+b \sin ^2(c+d x)} \, dx=\frac {(a+b) \log \left (a+b \sin ^2(c+d x)\right )}{2 a^2 d}-\frac {(a+b) \log (\sin (c+d x))}{a^2 d}-\frac {\csc ^2(c+d x)}{2 a d} \]
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Rule 78
Rule 3273
Rubi steps \begin{align*} \text {integral}& = \frac {\text {Subst}\left (\int \frac {1-x}{x^2 (a+b x)} \, dx,x,\sin ^2(c+d x)\right )}{2 d} \\ & = \frac {\text {Subst}\left (\int \left (\frac {1}{a x^2}+\frac {-a-b}{a^2 x}+\frac {b (a+b)}{a^2 (a+b x)}\right ) \, dx,x,\sin ^2(c+d x)\right )}{2 d} \\ & = -\frac {\csc ^2(c+d x)}{2 a d}-\frac {(a+b) \log (\sin (c+d x))}{a^2 d}+\frac {(a+b) \log \left (a+b \sin ^2(c+d x)\right )}{2 a^2 d} \\ \end{align*}
Time = 0.15 (sec) , antiderivative size = 50, normalized size of antiderivative = 0.79 \[ \int \frac {\cot ^3(c+d x)}{a+b \sin ^2(c+d x)} \, dx=-\frac {a \csc ^2(c+d x)+(a+b) \left (2 \log (\sin (c+d x))-\log \left (a+b \sin ^2(c+d x)\right )\right )}{2 a^2 d} \]
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Time = 1.85 (sec) , antiderivative size = 101, normalized size of antiderivative = 1.60
method | result | size |
derivativedivides | \(\frac {-\frac {1}{4 a \left (1+\cos \left (d x +c \right )\right )}+\frac {\left (-a -b \right ) \ln \left (1+\cos \left (d x +c \right )\right )}{2 a^{2}}+\frac {\left (a +b \right ) \ln \left (a +b -b \left (\cos ^{2}\left (d x +c \right )\right )\right )}{2 a^{2}}+\frac {1}{4 a \left (\cos \left (d x +c \right )-1\right )}+\frac {\left (-a -b \right ) \ln \left (\cos \left (d x +c \right )-1\right )}{2 a^{2}}}{d}\) | \(101\) |
default | \(\frac {-\frac {1}{4 a \left (1+\cos \left (d x +c \right )\right )}+\frac {\left (-a -b \right ) \ln \left (1+\cos \left (d x +c \right )\right )}{2 a^{2}}+\frac {\left (a +b \right ) \ln \left (a +b -b \left (\cos ^{2}\left (d x +c \right )\right )\right )}{2 a^{2}}+\frac {1}{4 a \left (\cos \left (d x +c \right )-1\right )}+\frac {\left (-a -b \right ) \ln \left (\cos \left (d x +c \right )-1\right )}{2 a^{2}}}{d}\) | \(101\) |
risch | \(\frac {2 \,{\mathrm e}^{2 i \left (d x +c \right )}}{d a \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right )^{2}}-\frac {\ln \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right )}{d a}-\frac {\ln \left ({\mathrm e}^{2 i \left (d x +c \right )}-1\right ) b}{a^{2} d}+\frac {\ln \left ({\mathrm e}^{4 i \left (d x +c \right )}-\frac {2 \left (2 a +b \right ) {\mathrm e}^{2 i \left (d x +c \right )}}{b}+1\right )}{2 a d}+\frac {\ln \left ({\mathrm e}^{4 i \left (d x +c \right )}-\frac {2 \left (2 a +b \right ) {\mathrm e}^{2 i \left (d x +c \right )}}{b}+1\right ) b}{2 a^{2} d}\) | \(152\) |
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Time = 0.32 (sec) , antiderivative size = 91, normalized size of antiderivative = 1.44 \[ \int \frac {\cot ^3(c+d x)}{a+b \sin ^2(c+d x)} \, dx=\frac {{\left ({\left (a + b\right )} \cos \left (d x + c\right )^{2} - a - b\right )} \log \left (-b \cos \left (d x + c\right )^{2} + a + b\right ) - 2 \, {\left ({\left (a + b\right )} \cos \left (d x + c\right )^{2} - a - b\right )} \log \left (\frac {1}{2} \, \sin \left (d x + c\right )\right ) + a}{2 \, {\left (a^{2} d \cos \left (d x + c\right )^{2} - a^{2} d\right )}} \]
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\[ \int \frac {\cot ^3(c+d x)}{a+b \sin ^2(c+d x)} \, dx=\int \frac {\cot ^{3}{\left (c + d x \right )}}{a + b \sin ^{2}{\left (c + d x \right )}}\, dx \]
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Time = 0.22 (sec) , antiderivative size = 56, normalized size of antiderivative = 0.89 \[ \int \frac {\cot ^3(c+d x)}{a+b \sin ^2(c+d x)} \, dx=\frac {\frac {{\left (a + b\right )} \log \left (b \sin \left (d x + c\right )^{2} + a\right )}{a^{2}} - \frac {{\left (a + b\right )} \log \left (\sin \left (d x + c\right )^{2}\right )}{a^{2}} - \frac {1}{a \sin \left (d x + c\right )^{2}}}{2 \, d} \]
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Time = 0.41 (sec) , antiderivative size = 108, normalized size of antiderivative = 1.71 \[ \int \frac {\cot ^3(c+d x)}{a+b \sin ^2(c+d x)} \, dx=\frac {\frac {\frac {\cos \left (d x + c\right ) + 1}{\cos \left (d x + c\right ) - 1} + \frac {\cos \left (d x + c\right ) - 1}{\cos \left (d x + c\right ) + 1}}{a} + \frac {4 \, {\left (a + b\right )} \log \left ({\left | -a {\left (\frac {\cos \left (d x + c\right ) + 1}{\cos \left (d x + c\right ) - 1} + \frac {\cos \left (d x + c\right ) - 1}{\cos \left (d x + c\right ) + 1}\right )} + 2 \, a + 4 \, b \right |}\right )}{a^{2}}}{8 \, d} \]
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Time = 14.13 (sec) , antiderivative size = 69, normalized size of antiderivative = 1.10 \[ \int \frac {\cot ^3(c+d x)}{a+b \sin ^2(c+d x)} \, dx=\frac {\ln \left (a+a\,{\mathrm {tan}\left (c+d\,x\right )}^2+b\,{\mathrm {tan}\left (c+d\,x\right )}^2\right )\,\left (a+b\right )}{2\,a^2\,d}-\frac {{\mathrm {cot}\left (c+d\,x\right )}^2}{2\,a\,d}-\frac {\ln \left (\mathrm {tan}\left (c+d\,x\right )\right )\,\left (a+b\right )}{a^2\,d} \]
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